You visit a zoo in Africa.

**There are zebras and ostriches in this Zoo.**

**You count 80 heads and 200 legs.**

**Can you find the number of Zebras and the number of Ostriches in the Zoo?**

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**Answer:**

To solve this riddle we will have to form equations.

Let the number of Zebras be Z &

the number of Ostriches be O.

Since there are 80 heads we can write;

Z + O = 80.—————————(1)

Since we know there are 200 legs in all and Ostrich has 2 legs whereas zebra has 4 legs we can write the following;

4Z + 2O = 200.———————-(2)

Multiplying 2 to equation (1) and then subtracting it from equation (2) we get;

4Z + 2O = 200

– 2Z – 2O = 160

2Z = 40

Z = 20.

Substituting value of Z in (1);

60 + O = 80

Therefore;

O = 60

**The number of Ostriches = 60 &**

**The number of Zebras = 20**