Fun With numbers Riddle: Find the Missing Number in The Given Picture

This is a very tricky riddle where you will have to think out of the box to solve it.

Let’s solve the equations first to get the value of the different shapes in the riddle.

Let’s rewrite the first equation as;

P + P + P = 45

Solving this we get;

3P = 45;

Hence;

P = 15

Let’s rewrite the second equation as;

C + C + P = 23

Solving this we get;

2C + P = 23

Substituting the value of P;

2C + 15 = 23

2C = 8

C = 4

Let’s rewrite the third equation as;

C + 3S + 3S = 10

substituting value of C we get;

4 + 6S = 10

6S = 6

Hence;

S = 1

Now the last equation has an unknown component which is similar to polygons.

So we count the numbers of sides which is: 6 + 5 + 4 = 15 (Hexagon +Pentagon + Rectangle)

So since the square is missing the value of 4 can be reduced from this;

Which will be 6 + 5 = 11 = PN.

So Let’s rewrite the last equation as;

2S + C + C x PN = ?

substituting the values we have got;

2 (1) + 4 + 4 x 11 = 2 + 4 + 44 = 50

Answer = 50