Find the Number From The Given Conditions
Have fun with numbers with this mathematical riddle.
There is a number:
If I divide it by 2, the remainder is 1.
If I divide it by 3, the remainder is 2.
If I divide it by 4, the remainder is 3.
If I divide it by 5, the remainder is 4.
If I divide it by 6, the remainder is 5.
If I divide it by 7, the remainder is 6.
If I divide it by 8, the remainder is 7.
If I divide it by 9, the remainder is 8.
If I divide it by 10, the remainder is 9.
There is a number:
| If I divide it by | the remainder is |
| 2 | 1 |
| 3 | 2 |
| 4 | 3 |
| 5 | 4 |
| 6 | 5 |
| 7 | 6 |
| 8 | 7 |
| 9 | 8 |
| 10 | 9 |
Can you find the smallest number which fulfills all this conditions?
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Answer:
To find the answer to this you need to know the basics of H.C.F. and L.C.M.
H.C.F. is the Highest Common Factor of the numbers, which in this case is 1
L.C.M. is the Lowest Common Multiple of the numbers, which is 2520 in this case.
To find the least number we need to subtract LCM – HCF;
So the answer is
LCM- HCF = 2520 – 1 = 2519
The smallest number which fulfills the conditions is = 2519